G'day noviceuser,

Based on the simplicity of your example arrays, and your subsequent "No, i have just started out perl sometimes back. Any regular way will work", you might be interested in this basic solution that doesn't employ modules. 

#!/usr/bin/env perl

use strict;
use warnings;

my @data = (
    [[qw{a b}], [qw{a b}]],
    [[qw{a b}], [qw{a}]],
    [[qw{a b}], [qw{a b c}]],
    [[qw{a b}], [qw{b 99 xyz}]],
);

for (@data) {
    my @ref = @{$_->[0]};
    my @test = @{$_->[1]};
    print "REF: '@ref' TEST: '@test'\n";
    my ($only_in_ref, $not_in_ref) = compare(\@ref, \@test);
    print "Only in REF: @{[sort keys %$only_in_ref]}\n";
    print "Not in REF:  @{[sort keys %$not_in_ref]}\n";
    print '-' x 40, "\n";
}

sub compare {
    my ($ref, $test) = @_;

    my %only_in_ref = map +($_ => 1), @$ref;
    my %not_in_ref;

    for (@$test) {
        if (exists $only_in_ref{$_}) {
            delete $only_in_ref{$_};
        }
        else {
            ++$not_in_ref{$_};
        }
    }

    return (\%only_in_ref, \%not_in_ref);
}

[download]

Output:

REF: 'a b' TEST: 'a b'
Only in REF:
Not in REF:
----------------------------------------
REF: 'a b' TEST: 'a'
Only in REF: b
Not in REF:
----------------------------------------
REF: 'a b' TEST: 'a b c'
Only in REF:
Not in REF:  c
----------------------------------------
REF: 'a b' TEST: 'b 99 xyz'
Only in REF: a
Not in REF:  99 xyz
----------------------------------------

[download]

— Ken

In reply to Re: compare two arrays if both are equal and have same elements irrespective of their position by kcott
in thread compare two arrays if both are equal and have same elements irrespective of their position by noviceuser

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