The answer to your question is hidden in the documentation for Integer Arithmetic. You need use integer; if you want your result as a signed integer. (By default it is treated as an unsigned integer.) Note also, that your << 28 assumes that your perl is compiled for 32-bit integers.
Bill

In reply to Re: Difference between Perl and Java for << operator? by BillKSmith
in thread Difference between Perl and Java for << operator? by davidfilmer

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