I think you might be misreading the glob.

The 5,2,1 maps 5 letters to one byte (look at the mapping hash with Data::Dump), so I'm getting a 5 to 1 reduction. (Ignoring the 2,1 which is just there for strings whose length is not a multiple of 5.)

I don't understand your use of 'chunks', or where you get 9 of them.

BTW: It's a 5 to 1 reduction independent of the redundancy in the string. Other compressors may use redundancy to do better. It's sort of a question of how random the letters really are.

In reply to Re^3: How to efficently pack a string of 63 characters by tybalt89
in thread How to efficently pack a string of 63 characters by baxy77bax

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