Just futzing around and I tried this: 

$ perl -le'print ~0'
18446744073709551615

$ perl -Mbigint -le'print +( 2 ** 64 ) - 1'
18446744073709551615

$ perl -le'print +( 2 ** 64 ) - 1'
1.84467440737096e+19

[download]

And also: 

$ perl -le'print 2 ** 49'
562949953421312

$ perl -le'print 2 ** 50'
1.12589990684262e+15

[download]

So why does perl convert a number that will obviously fit inside a 64 bit integer to floating point?

(Yes I read perlnumber.)

In reply to Non-integer print output??? by jwkrahn

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