> Note that the floating point value 1/3 is not the same as the rational value 1/3,

Good point, that might explain why it's considered undefined behavior by many.

And an approximation algorithm designed to work with floating point exponents won't be able to handle anything like 1/$odd differently.

Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery

In reply to Re^2: How to get better exponentiation? by LanX
in thread How to get better exponentiation? by Athanasius

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