I'd solve it this way:
sub two_sum_choroba {
my ($input, $target) = @_;
my %seen;
for my $i (0 .. $#$input) {
my $x = $input->[$i];
return [$i, $seen{ $target - $x }]
if exists $seen{ $target - $x };
$seen{$x} = $i;
}
}
It passes all the tests presented in the thread so far and benchmarks show it's also the fastest.
Translated to Python 3 (Dona eis requiem, smack), it was accepted by LeetCode as
Runtime: 48 ms, faster than 99.40% of Python3 online submissions for T
+wo Sum.
Memory Usage: 15.4 MB, less than 42.44% of Python3 online submissions
+for Two Sum.
map{substr$_->[0],$_->[1]||0,1}[\*||{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^*ARGV,3]
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