I'd solve it this way:
sub two_sum_choroba { my ($input, $target) = @_; my %seen; for my $i (0 .. $#$input) { my $x = $input->[$i]; return [$i, $seen{ $target - $x }] if exists $seen{ $target - $x }; $seen{$x} = $i; } }

It passes all the tests presented in the thread so far and benchmarks show it's also the fastest.

Translated to Python 3 (Dona eis requiem, smack), it was accepted by LeetCode as

Runtime: 48 ms, faster than 99.40% of Python3 online submissions for T +wo Sum. Memory Usage: 15.4 MB, less than 42.44% of Python3 online submissions +for Two Sum.

map{substr$_->[0],$_->[1]||0,1}[\*||{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^*ARGV,3]

In reply to Re: LeetCode Problem #1 - Two Sum - Improve and/or discuss. by choroba
in thread LeetCode Problem #1 - Two Sum - Improve and/or discuss. by kcott

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