O(N log N), O(N) if already sorted.

Rather than sorting the inputs, I would sort the indexes. That way, you wouldn't need an extra hash an array, just an array.

In reply to Re^2: LeetCode Problem #1 - Two Sum - Improve and/or discuss. by ikegami
in thread LeetCode Problem #1 - Two Sum - Improve and/or discuss. by kcott

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