Hi Monks!
I have the following hash ref:
{ '/a/b/c/dt/data/SUSE/tool/0.9.0' => '/a/b/c/dt/tools/SUSE/tool/0.9.0 +', '/nfs/us/tools/SUSE12' => '/usr/bin', '/a/b/c' => '/p' };
Each key is a path, which is the absolute path of the value. For example:
realpath /p # Yields /a/b/c
For each value, I would like to replace the substring with the other link, if such exists. In our case, we have '/a/b/c/dt/sde/tools/em64t_SUSE/tool/0.9.0' and '/a/b/c' => '/p', so I would like to have:
{ '/a/b/c/dt/data/SUSE/tool/0.9.0' => '/p/dt/tools/SUSE/tool/0.9.0', '/nfs/us/tools/SUSE12' => '/usr/bin', '/a/b/c' => '/p' };
I thought about doing the following - do two foreach loops on the keys (one nested inside the other). In the second loop, I would ignore the case where the two keys are the same. Then I would compare the values (if it starts with the value, then replace it). The current code that I code:
foreach my $actual_path_to_check (keys(%{$virtual_paths_href})) { foreach my $current_actual_path (keys(%{$virtual_paths_href})) { next if ($actual_path_to_check eq $current_actual_path); if ($virtual_paths_href->{$current_actual_path} =~ /^$virtual_ +paths_href->{$actual_path_to_check}/) { # Replace } } }
But then I figured that I don't know how many loops I would need. For example, if I have a case of a link which points to another link (like /x -> /y -> /z). In that case, I would need another loop over the values. The goal is to replace the substrings parts with the other links of other keys (not depending of the environment). How it can be done?

In reply to Replacing substrings with links by ovedpo15

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