> "bar"."\0"."123"

when using doublequotes or interpolated regexes one needs to escape a leading backslash, hence "\\0"

your code is not replacing the string '\0' but the chr(0) 

  DB<13> x "\0"
0  "\c@"
  DB<14> x chr(0)
0  "\c@"
  DB<15> x '\0' # with singlequotes escaping is only needed for \ and 
+'
0  '\\0'
  DB<16> p '\0' eq '\\0'
1

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Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery

In reply to Re^2: attempting to achieve something (escaping rules) by LanX
in thread attempting to achieve something by scientologyboxing

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