Hello, I am looking for a way to parse a file TXT with the underlying format. A office colleague praise for Ruby he uses to parse the file in " oneline" .

File.readlines("/home/user/objet_zone.don").reject{|l|}.map{|l|lf=l.st
+rip;(lf.size> 0 && lf[0..1]!="--") ? lf : nil}.compact.inject([]){|ar
+y,l|ary.last << l if (l=~/^[^=]+=>\s*debut/ && ary<<[])..(l=~/^[^=]+=
+>\s*fin/);ary}.map{|ary|ary[1..-2].map{|e|e.split('=>').map{|f|f.stri
+p.gsub('"','')}}.to_h}

[download]

the aim is to transform in hash every object (array of hash in his maner) for using them in the rest of the script.

he teaches me that the interval cames from Perl but i can't afford to traduce it ...

if (l=~/^[^=]+=>\s*debut/ && ary<<[])..(l=~/^[^=]+=>\s*fin/)

could you help me to proove him Perl is as efficient as Ruby ? (even if it is not a "oneline")

Thanks in advance

example of the file TXT :

objet => debut
index => 1
a => "premiere valeur"
...
z => "dernier mot"
objet => fin
...
objet => debut
index => 77
a => "autre valeur"
...
z => "aurai-je le dernier mot ?"
objet => fin

sorry for my poor english.

In reply to RESOLVED - parse a file TXT similar to XML by x-lours

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