$inRange = ($x > $a == $x < $b) || $x == $a || $x == $b; (inclusive)

Two thoughts:

1) Isn't that equivalent to: 
$inRange = ($x >= $a == $x <= $b);

[download]
Update: Yes, it isn't ;-) Thanks LanX.

2) Is it safe to assume that ($x > $a) and ($x < $b) will return the same value whenever they are true ?
It probably is ... but the docs merely say that they will return a true value, with no explicit guarantee that the magnitude of the "true value" will always be the same.

Cheers,
Rob

In reply to Re^2: Range check with unordered limits by syphilis
in thread Range check with unordered limits by hexcoder

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