The "OK" output is "1 2 3" (newlines instead of spaces), failure, as observed, is "1 1 1"
Hmmm ... if, in the script procided by the OP, I replace:
123 + 1 << 32
with
123 + (1 << 32)
and I replace:
456 + 1 << 32
with
456 + (1 << 32)
then I get the "OK" output of "1 2 3".
I wonder if that's what the OP meant to do ?
Given that "123 + 1 << 32" evaluates to exactly the same as "124 << 32", it seems strange to choose the former expression in preference to the latter.
Similarly "456 + 1 << 32" evaluates to exactly the same as "457 << 32".
Is the OP's problem no more than a typo ?
On a perl whose ivsize is 8 (bytes):
D:\>perl -le "print 'ok' if 123 + 1 << 32 == 124 << 32 && 456 + 1 << 3
+2 == 457 << 32;"
ok
Cheers,
Rob
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