Hi Monks, I have a problem. I would like to generate a random playlist for an old mxaudio program (SGI O2, perl version 5). My goal is to take the contents of a directory structure containing a very large number of audio files and generate a list of a given number (say 10 tracks) of unique mp3s. It is important that reading of the start folder is recursive and that it is possible to add exceptions. I attach the code as far as I have got. The unique list will add up, but if the random function selects the same file more than once, then of course with fewer items than I would like. Can you help me with this? Thanks Zsolt. 
#!/usr/bin/perl

my $target = "/home/zsolti/Temp";
my @exclude = (
  #'2023_02_21_Szentendre_Pilis_EK_oldal'
  'webftp'
 ,'x'
);
my (@audioFiles, %playList);
my $numOfRandFiles = 10;

&fileExplore($target);
#print join("\n", @audioFiles), "\n";

&uploadPlaylist;

print "-" x 80, "\n", "SELECTED FILES:\n", "-" x 80, "\n";
foreach $key (sort {$playList{$a} <=> $playList{$b}} (keys(%playList))
+) {
  print "$playList{$key}: $key\n";
}

sub fileExplore {
  my $dir = shift;
  my $hit = 0;
  local *DIR;
  opendir DIR, $dir or die "opendir $dir: $!";
  my $found = 0;
  while ($_ = readdir DIR) {
    next if /^\.{1,2}$/;
    $FSNode = $_;
    my $FSObj = "$dir/$FSNode";
    foreach my $exc (@exclude) {$hit = 1 if $FSObj =~ m/\/$exc\//g}
    next if $hit;
    if (-f $FSObj) {
      (my $fExt = $FSObj) =~ s/.*\.(.*$)/$1/i;
      push(@audioFiles, $FSObj) if lc($fExt) eq 'mp3';
    }
    fileExplore($FSObj) if -d $FSObj;
  }
  closedir DIR;
}

sub uploadPlaylist {
  for (my $i = 1; $i <= $numOfRandFiles; $i++) {
    $playList{$audioFiles[int rand@audioFiles]} = $i;
  }
}

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In reply to Add a fixed number of unique elements to hash by Vasek

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