I assume you want the cross-product of a list with itself.

sort can't do this because it's designed to be fast with O(n*log(n))

There used to be a way to change the applied algorithm, but that's deprecated now https://perldoc.perl.org/sort

Cheers Rolf
(addicted to the 𐍀𐌴𐍂𐌻 Programming Language :)
Wikisyntax for the Monastery

In reply to Re: sort of misunderstanding of sort by LanX
in thread sort of misunderstanding of sort by Discipulus

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