for my $c (1..$n1) {

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The list 1..$n1 is created in memory and then iterated over so $n1 is only evaluated once.

If you instead used a C style for loop then $n1 would be evaluated $n1 times.

Naked blocks are fun! -- Randal L. Schwartz, Perl hacker

In reply to Re: does a hash element as a loop parameter cause significant slowdown? by jwkrahn
in thread does a hash element as a loop parameter cause significant slowdown? by misterperl

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