I'm rather surprised they didn't optimize that to just iterate the hashtable directly.

You mean inline hv_iternext? The compiler will do that if appropriate. But that's unlikely since hv_iternext is quite big. It would make no sense to put a copy of that code in the function you showed.

How do you figure? It has to allocate the current size + 1.6MB of ram and initialize all of it.

No initialization is needed.

In reply to Re^12: Why does each() always re-evaluate its argument? ("for_list" ) by ikegami
in thread Why does each() always re-evaluate its argument? by Darkwing

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