Yes, because you separate the common case (non-magical) from the rare case with an if block, and then use the fast implementation most of the time. I didn't make up that example above, I copied it out of perl's own hv.c, where other various routines have been able to be optimized like that.

I also understand that there is probably a reason why they didn't optimize this case, but back to my original statement, it surprises me that this code path is using the normal iterator. I would think dumping the elements of a hash would be a frequent enough operation to be worth optimizing.

In reply to Re^15: Why does each() always re-evaluate its argument? ("for_list" ) by NERDVANA
in thread Why does each() always re-evaluate its argument? by Darkwing

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