So... how can a program open /dev/fd/63 if it doesn't exist?

Because it does exist at the time the command is run: 

$ echo <(echo foo) $(ls /dev/fd)
/dev/fd/63 0 1 2 3 63

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Greetings,
🐻

$gryYup$d0ylprbpriprrYpkJl2xyl~rzg??P~5lp2hyl0p$

In reply to Re^4: how perl do 'envsubst' by jo37
in thread how perl do 'envsubst' by vincentaxhe

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