nice info choroba. Glancing the doc you linked the following is even neater to my eyes:
my @match = grep /(?[ [a-z] - [aeiou] ])/, map chr, 0 .. 255;
L*
In reply to Re^2: JAVA [[a-z]&&[^aeiou]] equivalence
by Discipulus
in thread JAVA [[a-z]&&[^aeiou]] equivalence
by vincentaxhe
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