And because I, in turn, am me:
pdl> $n = sequence(15)+1 pdl> p $a = 1 + 1/$n [2 1.5 1.33333333333333 1.25 1.2 1.16666666666667 1.14285714285714 1.1 +25 1.11111111111111 1.1 1.09090909090909 1.08333333333333 1.076923076 +92308 1.07142857142857 1.06666666666667] pdl> p $s = $a->sumover 18.318228993229
I'm somewhat sure that took less time and was more maths-y than using OO ;-)

In reply to Re: Solving a maths problem with Perl by etj
in thread Solving a maths problem with Perl by tobyink

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