$ARGV[0] is my subroutine name, and $ARGV[1] it's arg. The sub is a method in a class and I blessed object $A with new(), that class has a sub with a name contained in $ARGV[0].

I researched using a variable as a sub name and found may examples with syntax like \$sub , &$sub , \&$sub, "do", "eval", even a seemingly unusual &{\&{$sub}}();

I can get some of these to work on a local sub, but not as part of my class object $A , trying syntax using those examples, like: 

%$A->$ARGV[0]( $ARGV[1] )
$A->$ARGV[0]( $ARGV[1] )
%{$A->$ARGV[0]( $ARGV[1] ) }
eval "$A->$ARGV[0]( $ARGV[1] )";
eval "{$A->$ARGV[0]( $ARGV[1] ) };"
$A->\$ARGV[0]( $ARGV[1] )

[download]
and like 27 other varieties. Can you (Rolf of course) suggest a syntax that works here?

TY!

In reply to How do I call a sub using a variable as its name, objectively by misterperl

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