print above_mean(@list_of_numbers);
Just as a matter of curiosity, you might try this variation on the quoted statement:
print above_mean();
Does calling the above_mean() function without any parameters make any difference to the value returned by the function? If not, why not?
Give a man a fish: <%-(-(-(-<
In reply to Re^3: [Homework Question] Subroutines & References
by AnomalousMonk
in thread [Homework Question] Subroutines & References
by Hayest
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