I'm not sure what your input was, but I generated mine with the following one-liner: 
perl -wE 'for (1..10000) { print int(rand 2) ? "xyzabcd" : ("mul(" . i
+nt(rand 5000). "," . int(rand 5000) . ")" ) ; print "\n" unless int r
+and 10 }' > 1

[download]

I then ran the two programs. Note that the one labelled "PYTHON" is in fact the Perl one, and vice versa.

These were my results: 

time python3 1.py 1
Found 200 matches.

real    0m0.027s
user    0m0.018s
sys    0m0.005s

$ time 1.pl 1
Found 200 matches.

real    0m0.006s
user    0m0.004s
sys    0m0.000s

[download]

YMMV.

map{substr$_->[0],$_->[1]||0,1}[\*||{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^*ARGV,3]

In reply to Re: Python regex faster than Perl? by choroba
in thread Python regex faster than Perl? by dave93

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