The discussion in this thread is about the side effects of implicit typecasting/conversions of whole numbers to augment precision when operations may cause an overflow.

Perl does this by switching to double floats with E0 were the mantissa has 53 bits (opposed to integers with 32 or 64 bits, depending on the built).

Now from what I read on Wikipedia is Rust strictly typed.

Hence I really don't understand what your code is supposed to show.

Is there any implicit typecasting in your code?°

update

According to this tutorial: https://oylenshpeegul.gitlab.io/from-perl-to-rust/numbers.html this can't be, because coercion has to be made explicitly.

Cheers Rolf
(addicted to the Perl Programming Language :)
see Wikisyntax for the Monastery

In reply to Re^4: Largest integer in 64-bit perl by LanX
in thread Largest integer in 64-bit perl by harangzsolt33

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