The first result is identical, you are adding 1 in Fortran only.

The second one needs 61 bits and is outside float precision in Perl.

Edit

This shows the same result and that the exponentiation is the real "culprit".

  DB<11> $x=1; $x*=3 for 1..38; say $x
1350851717672992089

  DB<12>

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Cheers Rolf
(addicted to the Perl Programming Language :)
see Wikisyntax for the Monastery

In reply to Re^6: Largest integer in 64-bit perl by LanX
in thread Largest integer in 64-bit perl by harangzsolt33

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