Oh oh, I see!! So, you get the value of $_[0] using shift, then you split the incoming string into individual characters, then you iterate through each character one by one performing this Chinese transform on each digit: 

$n = (0 . $n =~ tr/1-9/246802468/r | $n =~ tr/1-9/00001/r . $_) =~
    s/^0+(?=.)//r

I have no idea what I'm looking at, but I think, if I can ever come up with code like this, I will have become a Perl hacker. Haha for example, I don't understand how transforming digits from 1-9 into 246802468 is going to end up as a decimal in the end. So, I don't understand any of this. But I find it fascinating/amazing.

I'm Harangzsolt33, but somehow I got logged out.

In reply to Re^4: converting binary to decimal by Anonymous Monk
in thread converting binary to decimal by harangzsolt33

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