Delete returns the deleted value*s* (plural) of a slice and you didn't test a slice. ¹

Exists returns an (informal) Boolean (1 or dualvar ""/0) for a hash entry, and logically should also return a list of booleans in case of a slice.

Cheers Rolf

(addicted to the Perl Programming Language :)
see Wikisyntax for the Monastery

Edit

¹) From the docs of delete I already linked to

my %hash = (foo => 11, bar => 22, baz => 33); my $scalar = delete $hash{foo}; # $scalar is 11 $scalar = delete @hash{qw(foo bar)}; # $scalar is 22 my @array = delete @hash{qw(foo baz)}; # @array is (undef,33) <--- H +ERE

In reply to Re^4: Why doesn't exist work with hash slices? by LanX
in thread Why doesn't exist work with hash slices? by Anonymous Monk

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