In the first loop you check for $i being A and in the second for $i being B hence $i / $witness .

That's a different interpretation° of the task B = A * k , the OP was only doing the A part.

Cheers Rolf
(addicted to the Perl Programming Language :)
see Wikisyntax for the Monastery

°) According to Choroba that's the fun part of PWC ;-)

In reply to Re^2: Faster (but uglier) PWC 350-2 solutions by LanX
in thread Faster (but uglier) PWC 350-2 solutions by Anonymous Monk

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