But can ($var || 2) ever be false ?

No way I can see. So yes, the OPs code should be reducible to just $var; though that will produce a warning: Useless use of private variable in void context ....

And $var || 2; gets Useless use of a constant in void context ...

Replace the 2 with 1: $var || 1; to take advantage of a special case that produces no warning and deparses as:

C:\Users\HomeAdmin>perl -MO=Deparse -Mstrict -wle"my $var = 1; $var ||
+ 1;"
BEGIN { $^W = 1; }
BEGIN { $/ = "\n"; $\ = "\n"; }
use strict 'refs';
my $var = 1;
'???' unless $var;
-e syntax OK

[download]

Or:

1 if $var;

[download]

which achieves the same thing.

Or, if he's happy there are no ties involved, ditch the whole darn thing.

With the rise and rise of 'Social' network sites: 'Computers are making people easier to use everyday'
Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
"Science is about questioning the status quo. Questioning authority". I'm with torvalds on this
In the absence of evidence, opinion is indistinguishable from prejudice. Agile (and TDD) debunked

In reply to Re^5: Compiler Optimization by BrowserUk
in thread Compiler Optimization by three18ti

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