Should your code not be:

perl -e 'for my $i (1..63) {if(int(log(2**($i-1))/log(2)) != $i-1) {pr +int "$i\n"}}'

which gives no output for me.

UPDATE: Apologies, I think I get it now, the leading one of 2^i - 1 should be in the same place as the leading one for 2^(i-1) which is what you are testing.

My next thought was to use length(sprintf("%b",$x)) but that does not work either:

for my $i (1..63) { if(length(sprintf("%b",2**$i-1)) != length(sprintf("%b",2**($i-1)) +)) { print"$i\n"; printf("%b\n",2**($i-1)); printf("%b\n",(2**$i)-1); } }

In reply to Re: reliable get position of leftmost bit in large integers by hdb
in thread reliable get position of leftmost bit in large integers by wollmers

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