Given:

@b1 = (1,1,1,4,4);
@b2 = (1,2,3,4,6);

[download]

and desiring:

@b1 = (1,1,1,1,2);
@b2 = (3,4,4,4,6);

[download]

Why not use a sort algorithm to sorts the virtual array consisting of @b1 + @b2, using a function that maps the indices?

sub ind {
  $i = shift;
  if ($i <= $#b1) {
    return (\$b1[$i])
  } else {
    return (\$b2[$i-$#b1-1]) 
  }
}

[download]

This doesn't make any use of those free passes thru each buffer. But it also doesn't need an external buffer.

Dum Spiro Spero

In reply to Re: [OT] A measure of 'sortedness'? by GotToBTru
in thread [OT] A measure of 'sortedness'? by BrowserUk

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