perlop says

Note that both << and >> in Perl are implemented directly using << and >> in C
[...]
The result of overflowing the range of the integers is undefined because it is undefined also in C. In other words, using 32-bit integers, 1 << 32 is undefined. Shifting by a negative number of bits is also undefined.
Not Perl's fault indeed.

perl -E 'say unpack "b*", pack "Q", ( 3<<$_ ) for 60..70;'
0000000000000000000000000000000000000000000000000000000000001100
0000000000000000000000000000000000000000000000000000000000000110
0000000000000000000000000000000000000000000000000000000000000011
0000000000000000000000000000000000000000000000000000000000000001
1100000000000000000000000000000000000000000000000000000000000000
0110000000000000000000000000000000000000000000000000000000000000
0011000000000000000000000000000000000000000000000000000000000000
0001100000000000000000000000000000000000000000000000000000000000
0000110000000000000000000000000000000000000000000000000000000000
0000011000000000000000000000000000000000000000000000000000000000
0000001100000000000000000000000000000000000000000000000000000000

[download]

In reply to Re: Perl's bad at arithmetic? by Eily
in thread Perl's bad at arithmetic? by BrowserUk

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