"." needs to be escaped in regular expressions. Use s/\.{2}/,/g or s/[.]{2}/,/g. The former uses an escaped ".", the latter a character class containing only the "."

Alexander

Updated: First variant should be s/\.{2}/,/g, not s/\.{2}//,/g. Thanks to AnomalousMonk for spotting this bug.

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In reply to Re: Replace ".." with "," by afoken
in thread [solved] Replace ".." with "," by zaqwsxcde

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