This sounds like an iteration of this issue: Why it's stupid to `use a variable as a variable name' . See also, dynamic scalar names?, How can I use the value of a scalar as the name of an array variable?, and perlfaq7 (How can I use a variable as a variable name?) among others. Don’t feel bad if it’s what’s going on. It seems direct/correct at first to many hackers.

In reply to Re: Changing a variable which is a value of a hash by Your Mother
in thread Changing a variable which is a value of a hash by benedicth

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