I would probably do it like this:

use strict;
use warnings;

my @array1 = qw/ jed jethro zed zug /;
my @array2 = qw/ jed jed jed zack zed zug zug /;

print join(':', @$_), "\n" for count_occurrences( \@array1, \@array2 )
+;

sub count_occurrences {
    my( $wanted, $have ) = @_;
    my %counter;
    @counter{@$wanted} = (0)x@$wanted;
    $counter{$_}++ for @$have;
    return map { [ $_ => $counter{$_} ] } @$wanted;
}

[download]

The output is: 

jed:3
jethro:0
zed:1
zug:2

[download]

Notice how this method first sets counters to zero for all elements in @array1. Then it adds a count of those names in @array2 that appeared in @array1. Then a data structure is returned, and we print it.

The nuance here is that if a name appears in @array2 but not in @array1, it won't show up in the final count. After reading your question a couple of times, I got the impression that this behavior would be desirable. Another nuance is that the output will appear in the original order of names from @array1.


Dave

In reply to Re: Compare elements from two arrays and count by davido
in thread Compare elements from two arrays and count by skalman

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