I was under the impression that @_ would be passed to functions that were called with no arguments, like shift. This rings true except in the case of calling shift in package main, outside of a subroutine where it will shift of @ARGV. Why does it do this, and how can I get shift to work on @_ without copying @_ to @ARGV and not supplying arguments to shift? Or is this possible? Here is the code I've been playing with:
#!/usr/bin/perl -w use strict; @_ = qw( hello world ); ### prints everything in @ARGV but nothing in @_ while(my $d = shift) { print "$d\n"; } ### prints nothing because @ARGV is empty ### doesn't even print @_ contents while(my $n = shift) { print "$n\n"; }

In reply to @_ the default variable? by Anonymous Monk

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