Hello Monks, need your inputs on the below scenario I am trying to convert sql like operation on perl regular expression I have to compare two variable strings , one string is coming as sql like operator (%) 3 scenarios - 

foo% ( similar in perl ^foo+ ) 
%foo% ( similar in perl foo +)
%f%o%  ( no idea on perl)

[download]
I am not able to achieve this in perl , can someone help on this code 
$find1='%';
if ($field2_b ne "") { s/[^$find1]?^/\^/,s/[$find1]?$/+/ for $field2_b
+ };
if ($field1 =~ /$field2_b/i) { print "fields have pattern matching \n"
+;

[download]
Thanks,

In reply to Need to append and replace for % sign in a variable string by jayd11

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