So I found myself updating an old script (parses oodles of HTML files). and unknowingly introduced a subtle bug.
Here is a condensed version of the original code. The match is irrelevant.

my $k = ''; # A bunch of junk happens to this scalar before this point
my $t = "\ttest    \n     \n";
($k) = $t =~ /^\s*(.*?)\s*$/g;
print $k ."\n";

[download]

Without thinking, I made a subtle change.
my $k = ''; # A bunch of junk happens to this scalar before this point
my $t = "\ttest    \n     \n";
($k) .= $t =~ /^\s*(.*?)\s*$/g;
print $k ."\n";

[download]

A '1' kept getting shoved into $k. Goes without saying that I spend hours chasing this new bug down until I realized I was trying to use a list in a scalar context. So after much cursing I went and fixed the bug like thus.
my $k = ''; # A bunch of junk happens to this scalar before this point
my $t = "\ttest    \n     \n";
$t =~ /^\s*(.*?)\s*$/g;
($k) .= $1;
print $k ."\n";

[download]

After a fashion, I got to thinking. Is there a way to get it back to a one liner again and still append the value of $1 to $k? I tried several variations on the original but can't seem to work out a solution. My thought was something along the lines of:
my $k = ''; # A bunch of junk happens to this scalar before this point
my $t = "\ttest    \n     \n";
($k) .= $($t =~ /^\s*(.*?)\s*$/g)[0];
print $k ."\n";

[download]

I tried several variations but I can't quite seem to get it right. My gut says it should be feasible, but my brain can't quite put it together
Any ideas?

In reply to Appending a single Scalar after a match by SavannahLion

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