Hmm, three small things.

`ls -ltr /tmp` does not give you a list of files, but a list of files with their attributes and characteristics, while you need the bare file names. Also note that you need a semi-colon at the end of that line;

When you try your scp $output command, you fail to specify the path to $output (/tmp), so that your program is unlikely to find it.

In this line: 

system("scp $output user@server:/tmp/LOGS");

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you need to escape the @ to prevent Perl from thinking you are trying to manipulate an array called @server. So, something like this: 
system("scp $output user\@server:/tmp/LOGS");

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When trying to do such things, I usually find it convenient to build my full command into a variable and to print that variable to check exactly which command I'll issue to the system. Something like this: 
my $command = "scp $output user\@server:/tmp/LOGS";
print "Issuing this command: $command\n";
system("$command");

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In reply to Re: scp output without having to use "Net::SCP" in Perl by Laurent_R
in thread scp output without having to use "Net::SCP" in Perl by pjzero@90

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