Until you add it to a value in the range -1.xe0 .. 1.xe0; then it disappears.

Right. I had forgotten the addition from your original post.

I'm thinking that cascading 3 or 4 32 bit integers (as I demonstrated in an earlier post) to create 96 or 128 bit integers will get you what you are looking for.

In reply to Re^7: Need more precision. by RonW
in thread Need more precision. by BrowserUk

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