#!/usr/bin/perl -w 
use strict;

my @a1 = qw(My name is Andrew);
my @a2 = qw(My dog named  Andrew);
my $i;
my $a = 0;
my $s = 0;
my $z = 0;
my $aa;
my $ss;
my $n = "\n";
my $t = "\t";

foreach my $a1 (@a1){
$i++;
#print $a1 . "\n"; 
}

First:for($a = 0; $a <= $i; $a++){
        Second:for($s = 0; $s <= $i; $s++){
        my $d = 0;
        print $a.$t;
        print $s.$n;
        if($a!=$s){
        print "Yes.->".$a.$s.$n; last}
        print "system command \$a $a, then for \$s $s".$n;
        $d++;
        }

}

[download]

What I am trying to do here, use this nested for loop to get numbers that don't match. I need this to be continous, as this is a blueprint for another project. Now it appears that when I do the code, I get this, 

0    0
system command $a 0, then for $s 0
0    1
Yes.->01
1    0
Yes.->10
2    0
Yes.->20
3    0
Yes.->30
4    0
Yes.->40

[download]
when i need it to do this 
system command $a 0, then for $s 0
system command $a 0, then for $s 1
system command $a 0, then for $s 2
system command $a 0, then for $s 3
system command $a 0, then for $s 4
system command $a 1, then for $s 0
system command $a 1, then for $s 1
system command $a 1, then for $s 2
.... and so on and so on.

[download]
My problem is that I can't seem to get the script to loop through the for loops after the $_'s go through the boolean statements. It seems the boolean statements cause the for loops to not progress. I need to have the boolean statements to get unequal numbers. This is the best I can explain it. Any tips. Cheers

In reply to how to repeat a if else statement in a nested for loop by ajl412860

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