byteorder is 12345678 on that platform.
That is a completely meaningless statement:
print $Config{ archname };;
MSWin32-x64-multi-thread
$n = 0x12345678;;
print unpack 'C*', pack 'V', $n;;
120 86 52 18
print unpack 'C*', pack 'NV', $n;;
18 52 86 120 0 0 0 0
print unpack 'C*', pack 'N', $n;;
18 52 86 120
print unpack 'C*', pack 'Q<', $n;;
120 86 52 18 0 0 0 0
print unpack 'C*', pack 'Q>', $n;;
0 0 0 0 18 52 86 120
Until you define what the phrase "byteorder is 12345678" means; it means nothing useful.
It could mean:
- The decimal value 12345678, is stored in memory as ...
- Or, the eight bytes of a 32-bit value are stored in memory as ...
- Or, the hex value 12345678 is stored in memory as ...
- Or, the sequence of ascii characters 12345678 is stored in memory as ...
Except that the ... in any of those statements is not specified; which renders the statement -- whatever the intended interpretation -- completely meaningless.
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