You replied to a 4 years old thread. Moreover, you check half the pairs pointlessly - there's no need to check
$arr[$#arr] versus
$arr[0], when you've already checked
$arr[0] versus
$arr[$#arr].
Here's how I'd code your idea:
#!/usr/bin/perl
use strict;
use warnings;
chomp(my $name = <>);
my @arr = split //, $name;
my $is_palindrome = 1;
for my $i (0 .. $#arr / 2) {
# warn "$arr[$i] eq $arr[ -$i - 1 ]";
if ($arr[$i] ne $arr[ -$i - 1 ]) {
undef $is_palindrome;
last
}
}
print 'Word is',
$is_palindrome ? q() : ' not',
" a palindrome!!!\n";
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