BrianP,

You have to go back to the math. 8bit or 128bit machines can get the same answer, it's knowing how the bits need to be put together :-)

For you: Yes, for me, 32bits are fine for 98% of my work. All of my servers have at least 16GB, and many have many times that amount. But I can use 32bit Perl for 98% of the work (smaller footprint), and 64 bit Perl for the rest. I also have 32bit Perl with 64bit Integers.

You are used to working with decimal numbers, but pack/unpack can be used to convert between binary, octal, decimal and hexadecimal. To use 48bit RGB, just think of the 6 octets as 3 16 bit numbers. Then this works: 

my $myNum = 65000 * (2**32);
my ( $R,$G,$B ) = unpack("nnn", $myNum );
print "\$myNum: $myNum\n(\$R,\$G,\$B): $R\t$G\t$B\n";

[download]
A lot of monks here are better at the math than I, but I can hold my own most of the time!

For the future, ask specific questions that show your problem and when possible show the code that's demonstrating the problem. For your initial problem, you didn't have to worry about endianess, but you may have to consider it if your working with different architectures.

Good Luck...Ed

Regards...Ed

"Well done is better than well said." - Benjamin Franklin

In reply to Re^3: Perl Hashes in C? by flexvault
in thread Perl Hashes in C? by BrianP

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