Hmm... perhaps you think I didn't read the documentation you linked to? I did, twice, but that didn't get me very far. Which either says something about my comprehension, or the quality of the documentation.
$? is a perl variable. Presumably, in the case we are discussing, print/write to a closed pipe results in $? being set, and presumably that is also what perl ends up passing back to the shell, which shifts it by 8 and eventually I end up seeing it as an integer.
How does the documentation for $? supposed to get me from the number 141 back to SIGPIPE?
update: So it turns out the shell exit code is $? directly, and not shifted like I thought. Hence:
And now I see that I have something I can look up in signum.h.141 >> 8 = 0 141 & 127 = 13 141 & 128 = 128
In reply to Re^4: Unexpected termination on "print" (docs)
by mlawren
in thread Unexpected termination on "print"
by mlawren
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