Hello rsFalse,

Is it true that ($match){1}+ equals to simply $match?

Yes, and the + does nothing here, as you can see with use warnings:

use strict;
use warnings;

chomp(my $match = <DATA>);
chomp(   $_     = <DATA>);

for my $regex (
                  "($match){1}+",
                  "($match){1}",
                  "($match)",
                  "($match)+",
                  "($match)+?",
              )
{
    print qw(FAIL SUCCESS)[ !! m/\A $regex \z/x ], "\n"
}

__DATA__
(a|b){2}
bbab
[download]

Output:

22:21 >perl 1345_SoPW.pl
Useless use of greediness modifier '+' in regex; marked by <-- HERE in
+ m/\A ((a|b){2}){1}+ <-- HERE  \z/ at 1345_SoPW.pl line 27, <DATA> li
+ne 2.
FAIL
FAIL
FAIL
SUCCESS
SUCCESS

22:21 >
[download]

Hope that helps,