This post http://www.daemon.de/blog/2014/12/30/383/re-perl-jam-exploiting-20-year-old-vulnerability-31c3/ details a claim that perl has a security flaw, and rejects that claim.

Apparently this:

my @a = qw(8 foo 666); my %h = (foo => 100, bar => 333, san => @a); print Dumper(\%h); $VAR1 = { 'san' => 8, 'bar' => 333, 'foo' => 666 };

Is expected behaviour and not a problem. Happy to accept that, but can someone talk me through it? I've been working with perl for many years and never heard the word "dissolve" used before.


In reply to Why does an array "dissolve" into a hash? by Cody Fendant

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