Hi, I am new to Perl, learning how to parse a linux log file. So, I grep sth from the log, serving as input to m parse script and print the result to a proper format.

[linux host] $ grep "Something" sample.log | perl myParser.pl 

my $line;
foreach $line (<>) {
...
}

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This works fine, but I would like to supply more parameter to my perl script to determine the format style, eg. 

$ grep "Something" sample.log | perl myParser.pl VERTICAL

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will print the result vertically, 
$ grep "Something" sample.log | perl myParser.pl COLUMN

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will print the result in columnized format.

I tried to capture it by $ARGV[0], $ARGV1, but still failed. Please kindly help

More, i did a simple test 

#!/usr/bin/perl
use strict;
my $param0 = $ARGV[0];
my $line;

print "\nFirst Arguement is : $param0";

foreach $line (<>) {
...
}

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$ grep "Name=" sample.log | perl SimpleTest.pl VERTICAL 

Can't open VERTICAL: No such file or directory at SimpleTest.pl line 1
+1.
First Arguement is : VERTICAL

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Then , it just stopped and not execute the foreach loop

In reply to More Arguments by joaming

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