Adding to the ?above —

A generic solution must escape the escape character also, otherwise the transformation isn't reversible. 

{ my %T = ("\n" => "\\n", "\r" => "\\r", "\\" => "\\\\");
  sub escape { s/[\r\n\\]/$T{$&}/g for @_ }
}

[download]

In reply to Re: Transforming "\r\n" to '\012\015' by Anonymous Monk
in thread Transforming "\r\n" to '\012\015' by stevieb

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