Well the same critic applies to "last here" so I'll rather stick with its criteria.

I'd probably start by storing the last n ( =10 ?) "last here" on a daily resolution.

Calculating with the above formula is easy ( diff(oldest, newest) / n ), and you just need to replace the oldest record on a new day.

Cheers Rolf
(addicted to the Perl Programming Language and ☆☆☆☆ :)
Je suis Charlie!

In reply to Re^4: here frequency ? by LanX
in thread here frequency ? by LanX

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